Solutie3

Numarul dat se poate scrie astfel: 1 + 3 + 32(1 + 3 + 32 + 33 + 34) + 37(1 + 3 + 32 + …+ 34) + …+

32002(1 + 3 + 32 + 33 + 34) = 4 + 121(32 + 37 + …+ 32002) = 4 + M121

Deci restul cautat este 4.

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